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The yield of methyl benzoate was 6.4 g.
|
C6H5COOH (122 g) ⇒ C6H5COOCH3 (136 g) |
So, from 8 g of benzoic acid, the theoretical yield of methyl benzoate is 136/122 × 8 = 8.9 g
\Percentage yield = 6.4/8.9 × 100 = 72%