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The equation for this reaction is:
|
6KOH(aq) + 3I2(aq) ⇒ 5KI(aq) + KIO3 (aq) + 3H2O(aq) |
We reacted all of the potassium hydroxide present in the solution. We need to be able to work out the number of moles from the concentration:
Number of moles of KOH = 4 ´ 10/1000 = 0.04 mol
According to the equation 6 moles of potassium hydroxide should produce 1 mole of KIO3
| 6KOH º KIO3 | \ Number of moles of KIO3 = 0.04/6 |
| KIO3 = 214 | \ Mass of moles of KIO3 = 0.04/6 ´ 214 = 1.43 g |
We are unlikely to obtain this quantity, as some of the product will still be dissolved in the water at the filtration stage.