ISSR CLASSES
Checkpoint Science
iGCSE Chemistry
iGCSE Physics
iGCSE Coordinated Science
A-Level Chemistry
PRACTICALS
Practicals Home
Practicals A-Z
Study Plan for Practical Work
0.050 g of lithium is 0.050 ÷ 6.94 = 0.0072 mol of Li
Assuming molar gas volume at RTP = 24000 cm3 mol-1
We collected 83 cm3 of hydrogen gas
83 ÷ 24000 = 0.0035 mol of H2
This give a ratio Li:H2 of 0.0072/0.0035:1 or 2.06:1
2 Li to 1 H2 clearly shows that equation 1 must be the correct one:
|
1. |
2Li(s) + 2H2O(l) ⇒ 2LiOH(aq) + H2(g) |