ISSR CLASSES
Checkpoint Science
iGCSE Chemistry
iGCSE Physics
iGCSE Coordinated Science
A-Level Chemistry
PRACTICALS
Practicals Home
Practicals A-Z
Study Plan for Practical Work
You should have worked out the following equation:
|
Fe2O3(s) + 2Al(s) ⇒ 2Fe(l) + Al2O3(s) |
Fe2O3 = 160, so 100 g is 100/160 = 0.625 mols
Fe2O3 º 2Al
\ number of moles of Al = 2 × 0.625 = 1.25
Al = 27
\ mass of Al = 1.25 × 27 = 33.8 g