We know from the reactivity series that iron is more reactive than copper, and so should displace the copper from its compounds. However, iron forms two series of compounds - one containing the iron(II) ion and one containing the iron(III) ion. The purpose of this experiment is to carry out a gravimetric analysis in order to deduce which iron compound is formed in this reaction. The two possible equations are:
|
1. |
Fe(s) + Cu2+(aq) ® Fe2+(aq) + Cu(s) |
|
2. |
2Fe(s) + 3Cu2+(aq) ⇒ 2Fe3+(aq) + 3Cu(s) |
We shall weigh out exactly 0.01 moles of iron powder (0.56 g) and react it with excess copper(II) sulfate solution. If equation 1 is correct we would expect to obtain 0.01 moles of copper (a 1:1 ratio), but if equation 2 is correct we would expect to obtain 0.015 moles of copper (a 2:3 ratio). Watch the video and deduce which equation is the correct one. Check your conclusion here.
Video - the reaction of iron with copper(II) sulfate